Convert 64 bits binary string to BigInteger and maintain the sign

Convert 64 bits binary string to BigInteger and maintain the sign

2022/05/08 Java Programming 0

The first and third method converted successfully with sign. The second one fail. The reason 3rd way working is : It convert to biginteger and convert to long (then we have sign),then convert back to biginteger (also with sign)

		BigInteger i = BigInteger.valueOf(0xfffffffffffffff7l);
		System.out.println(i);
		System.out.println(i.toString(16));
		System.out.println(String.valueOf(i.toString(16)));

		BigInteger i2 = new BigInteger("1111111111111111111111111111111111111111111111111111111111110111", 2);
		System.out.println(i2);
		System.out.println(i2.toString(16));
		System.out.println(String.valueOf(i2.toString(16)));

		BigInteger i3 = BigInteger.valueOf(new BigInteger("1111111111111111111111111111111111111111111111111111111111110111", 2).longValue());
		System.out.println(i3);
		System.out.println(i3.toString(16));
		System.out.println(String.valueOf(i3.toString(16)));

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